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Compare a string with the string.
template< [role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type]> constexpr int compare( const T& t) const;
Let s
be string_view_type(t)
and comp
be traits_type::compare(data()
,
s.data(), std::min(size()
,
s.size()). If comp !=
0
, then the result is comp
. Otherwise, the result is 0
if size()
== s.size(), -1
if size()
< s.size(), and 1
otherwise.
Linear.
Strong guarantee.
Type |
Description |
---|---|
|
The type of the object to convert. |
std::is_convertible<const T&, string_view>::value && !std::is_convertible<const T&, const_pointer>::value.
The result of lexicographically comparing s
and the string.
Name |
Description |
---|---|
|
The string to compare. |