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Předcházející | Další |
unset() destroys the specified variables. Note that in PHP 3, unset() will always return TRUE (actually, the integer value 1). In PHP 4, however, unset() is no longer a true function: it is now a statement. As such no value is returned, and attempting to take the value of unset() results in a parse error.
The behavior of unset() inside of a function can vary depending on what type of variable you are attempting to destroy.
If a globalized variable is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called.
The above example would output:If a variable that is PASSED BY REFERENCE is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called.
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If a static variable is unset() inside of a function, unset() destroys the variable and all its references.
The above example would output:If you would like to unset() a global variable inside of a function, you can use the $GLOBALS array to do so:
Poznámka: Protože se jedná o jazykový konstrukt a ne o funkci, nemůžete ho volat pomocí funkcí v proměnných
See also isset(), empty(), and array_splice().
Předcházející | Domů | Další |
unserialize | Nahoru | var_dump |